Class Notes (October 15, 2007)




1) First, today we created live bookmarks so that we can tell when someone has made a post.

2) We went over the problem number 3 from the homework on page 79:
One important idea is that m(x) is a slope function. One can define the slope function by:

scribe-10-15.jpg
m(x)= x-3 if x is not equal to 5
**(this represents the slope of the secant line for the every line going through the point (5,3) when x is not equal to 5

***Very Important concept: The limit of the average rate (slope of the secant line) = the instantaneous rate (slope of the tangent line)

graphic-_2-10-15.jpg
so 2 is the slope of the tangent line at x=4

3) Then we went to the Derivative plotter on Mrs. Evrard’s homepage
-This site can help you practice finding the derivative function for different graphs.

4) Then we worked on Exploration 3-2: Exact Vale of a Derivative
Given the function 3rd-1-15.jpg one can find f’(4) in a similar way to problem #3

4th-10-15.jpg

(In order to get from the 3rd step to the 4th step (shown above) you have to use synthetic division)

Then you can find the tangent line at x=4 because you have the points (4, f (4))- which are (4,10) and the slope f’(4)= 7
So y=7(x-4)+10

5) We then completed problem #5 on the Exploration 3-2 worksheet
(This problem follows the same method as described above but uses f’(2) instead)

The homework tonight is p.81-83 All Qs #1, 2, 3-19 odd, 20
Also remember Quiz on Friday!


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2 Responses to “Class Notes (October 15, 2007)”

  1.    scribe Says:

    Well done. It’s detailed and easy to follow. CE

  2.    secant graphs Says:

    [...] on page 79: One important idea is that mx is a slope function. One can define the slope function by:http://cevrard3.edublogs.org/2007/10/15/class-notes-october-15-2007/Exploration 24: Sinusoidal Equations from GraphsFile Format: PDF/Adobe Acrobat – View as [...]

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