1/4/10 MW

January 6th, 2010

Picture 3

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Picture 5

Class Notes 12/17 EG

January 6th, 2010

We worked on related rates packet. The problem below is from the first page of the packet.

Picture 12

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Picture 17

NO HOMEWORK, VACATION!!!

Related Rates 12/17 LizF

December 17th, 2009

During class we did a group quiz re-take.  Then Mrs. Everard quickly introduced Related Rates.
Hw is finish the MC
Example number 1 from page 517
Find how fast z is changing when x=10

600=rate of change for x

Picture 19

kh 12/11

December 14th, 2009

Derivative=Continuity≠ Differenciation

Hw pg 158 problem 31

Homeworkpg158

pg 161

x(t)

Picture 1

pg161

Class Notes: 12/7

December 10th, 2009

Derivative of Inverse Functions:

Restrictions on the domain of the original function

Restrictions on the range of the inverse function

Sin

Graph:
11429.nfg005

Cos

cos_inv_graph

Inverse of Inverse Tangent:

image001

Inverse of Cosecant

CosecentInverse

Graph of Inverse Cosecant:

arccsc

Inverse of Cotangent:

Inverse Cotangent

Graph of Inverse Cotangent:

OC0111133_Trig8005

Sample Problem:

SampleProblem

Answers to 14-24 on Pg.151

SampleProblems

Hw: Do 13-33 Odd on Pg.157

December 7th, 2009

Inverse Trigonometric Functions

inversetrigfunct*see page 148 for graphs

 \begin{eqnarray*}  y & = & \tan^{-1}(x) \\  \tan(y) & = & x \\ \\  \sec^2(y) \frac{dy}{dx} & = & 1 \\ \\  (1 + \tan^2(y)) \frac{dy}{dx} & = & 1 \\ \\  (1 + x^2)\frac{dy}{dx} & = & 1 \\ \\  \frac{dy}{dx} & = & \frac{1}{1+x^2}  \end{eqnarray*}

 \begin{eqnarray*}  \frac{d}{dx} \sin^{-1}(x)  & = & \frac{1}{\sqrt{1-x^2}} \\  \frac{d}{dx} \cos^{-1}(x)  & = & -\frac{1}{\sqrt{1-x^2}}  \end{eqnarray*}

\[  \frac{d}{dx} \tan^{-1}(x) = \frac 1{1+x^2}   \]

\begin{align} \frac{d}{dx} \arcsin x & {}= \frac{1}{\sqrt{1-x^2}}\\ \frac{d}{dx} \arccos x & {}= \frac{-1}{\sqrt{1-x^2}}\\ \frac{d}{dx} \arctan x & {}= \frac{1}{1+x^2}\\ \frac{d}{dx} \arccot x & {}= \frac{-1}{1+x^2}\\ \frac{d}{dx} \arcsec x & {}= \frac{1}{x\,\sqrt{x^2-1}}\\ \frac{d}{dx} \arccsc x & {}= \frac{-1}{x\,\sqrt{x^2-1}} \end{align}

HW: Derive inverse csc, sec, cot

Also: pg.152 13-21 odd

December 1 BJ

December 2nd, 2009

In class we went over the second Derivative Quiz and completed a worksheet on Implicit Differentiation.

Bonus problem on the quiz:

Calc Scribe Notes

Implicit Differentiation problem: #12 on pg. 171

Calc Scribe Notes 2

Homework:

- Read Section 4-5 on pgs. 145-148

- Review trig identities and the unit circle for a trigonometry quiz next class

Natural Logs LizF

November 30th, 2009

In class we found the derivative of natural logs and exponential functions

Nat

Derived that the derivative for the natural log is one over the argument
Picture 7

So…
Picture 8

To find the derivative of an exponential function take the natural logs of both sides. Don’t forget that y is a function of x so the chain rule applies.
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Picture 10

11/20/09, HarryP

November 20th, 2009

notesfinal

Homework due next class-

Test Corrections

1,3,5 on page 171

Question 3 of Part II implicit class sheet

11/18/2009 AS

November 20th, 2009

In class we went over the homework. Here are the problems we went over and the equations we went over.

notes

The homework is to finish test corrections for tuesday, and study for a quiz on identities and the unit circle.